XAT Question Paper 2008 with solution Free Download pdf

XAT Question Paper 2008 with solution Free Download pdfXAT Question Paper 2008 with solution Free Download pdf.

XAT Question Paper 2008 with Solution Free Download PDF Xavier MBA Admission Entrance Test 2008 XAT 2008 Question Paper, This XAT 2008 Question will help all the students for their exam preparation, here the question type is MCQ i.e multiple choice question answers, if this XAT 2008 question paper in pdf file for XAT you can download it in FREE, if XAT 2008 paper in text for XAT you can download XAT 2008 page also just Go to menu bar, Click on File->then Save.

XAT Question Paper 2008 with solution Free Download pdf.

XAT 2012 Paper will have

Reading Comprehension & English – 40 Questions,Quantitative Ability – 44 Questions,Data Interpretation and Reasoning – 43 Questions Paper

In Similar Links you can also have XAT Preparation Tips XAT exam 2012, XAT Question Bank or XAT Reference Books or Study Materials XAT

1. Four digits of the number 29138576 are omitted so that the result is as large as possible. The largest omitted digit is
(A) 9 (B) 8 (C) 7 (D) 6 (E) 5

Solution: We have to omit four digits in such a manner that we get the largest possible number as the result. ∴We will omit 2, 1, 3 and 5 and the result will be 9876. ∴ The largest omitted digit will be 5. Hence, option E.

 

If 20% of the girls opt for HR electives, then the total number of boys in the second year is
(A) 54 (B) 53 (C) 52 (D) 51 (E) 50

Hence, option D.

Rajiv is a student in a business school. After every test he calculates his cumulative average. QT and OB were his last two tests. 83 marks in QT increased his average by 2. 75 marks in OB further increased his average by 1. Reasoning is the next test, if he gets 51 in Reasoning, his average will be _____?
(A) 63 (B) 62 (C) 61 (D) 60 (E) 59

Hence, option A.

If F(x, n) be the number of ways of distributing “x” toys to “n” children so that each child receives at the most 2 toys then F(4, 3) = _______?
(A) 2 (B) 3 (C) 4 (D) 5 (E) 6

Solution: ∴ We have to find the number of ways in which 4 toys can be distributed to 3 children so that each child receives at the most 2 toys. There are two possible cases:
Case 1: Two of them receive 2 toys each and one of them doesn‟t get any toy. There are 3 possible ways to distribute the toys in this case i.e., the three possible ways of selecting the child who will not get any toy.
Case 2: Two of them receive 1 toy each and one of them receives 2 toys. Again there are 3 possible ways to distribute the toys in this case i.e., the three possible ways of selecting the child who will get 2 toys. ∴ There are a total of 6 possible ways.

option E.
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