JAM Question Paper 2019-20 MA (Mathematics)

JAM Question Paper 2019-20 MA (Mathematics).

JAM Question Paper 2019-20 MA MathematicsJAM MA – Mathematics 2019-20 Question Paper test papers will be fully objective type.  This JAM MA – Mathematics 2019-20 Question will help all the students for their exam preparation, here the question type is MCQ i.e multiple choice question answers, if this JAM MA – Mathematics 2019-20 question paper in pdf file for IIT JAM MA – Mathematics you can download it in FREE, if Joint Entrance Examination (JAM) 2019-20 paper in text for JAM you can download JAM 2019-20 page also just Go to menu bar, Click on File->then Save.

JAM Question Paper 2019-20 MA (Mathematics).

JAM MA – Mathematics 2019-20 Question paper Free Download PDF is available in www.oldquestionpapers.net which has been provided by many students this Joint Admission Test i.e. JAM MA – Mathematics 2019-20 paper is available for all the students in FREE and also IIT JAM Mathematics 2019-20 question paper fully solved i.e. with answer keys and solution.

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01. There are two boxes, each containing two components. Each component is defective with probability 1/4, independent of all other components. The probability that exactly one box contains exactly one defective component equals

  • (A) 3/8
  • (B) 5/8
  • (C) 15/32
  • (D) 17/32

02. Let X and Y be two independent random variables such that X ~ (0,2) and Y ~ U (1,3) Then P(X < Y) equals

  • (A) 1/2
  • (B) 3/4
  • (C) 7/8
  • (D) 1

03. 2000 cashew nuts are mixed thoroughly in flour. The entire mixture is divided into 1000 equal parts and each part is used to make one biscuit. Assume that no cashews are broken in the process. A biscuit is picked at random. The probability that it contains no cashew nuts is

  • (A) between 0 and 0.1
  • (B) between 0.1 and 0.2
  • (C) between 0.2 and 0.3
  • (D) between 0.3 and 0.4

04. Let f: (0, ¥) ® ℝ Let be given by

f(x) = log x – x + 2

Then, the number of roots of f is

  • (A) 0
  • (B) 1
  • (C) 2
  • (D) 3

05. Let f:ℝ ® ℝ be defined by f (x) = x(x – 1)(x – 2). Then

  • (A) f is one-one and onto
  • (B) f is neither one-one nor onto
  • (C) f is one-one but not onto
  • (D) f is not one-one but onto

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