GATE CS IT Question Paper 1994.
GATE CS IT Question Paper 1994 with Answers Solution Computer Science Information Technology 1994
GATE i.e. Graduate Aptitude Test in Engineering Computer Science Information Technology 1994 Exam Has been Conducted by IISc Bangalore IIT Bombay IIT Delhi IIT Guwahati IIT Kanpur IIT Kharagpur IIT Madras IIT Roorkee. This GATE CS IT 1994 examination is the procedure to get the admission in M.Tech
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GATE CS IT Question Paper 1994
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Section — A
1. Choose one of the alternatives for the following questions:
1.1 FORTRAN implementation do not permit recursion because
(a) they use static allocation for variables
(b) they use dynamic allocation for variables
(c) stacks are not available on all machines
(d) it is not possible to implement recursion on all machines
1.5 An unrestricted use of the goto statement is harmful because
(a) it makes it more difficult to verify programs
(b) it increases the running time of the programs
(c) it increases the memory required for the programs
(d) it results in the compiler generating longer machine code
1.6 The number of distinct simple graphs with upto three nodes is
(a) 15 (b) 10 (c) 7 (d)9
1.12 Generation of intermediate code based on an abstract machine model is useful in compilers because
(a) it makes implementation of lexical analysis and syntax analysis easier
(b) syntax-directed translations can be written for intermediate code generation
(c) it enhances the portability of the front end of the compiler
(d) it is not possible to generate code for real machines directly from high level language programs
1.13 A memory page containing a heavily used variable that was initialized very early and is in constant use is removed when
(a) LRU page replacement algorithm is used
(b) FIFO page replacement algorithm is used
(c) LFU page replacement algorithm is used
(d) None of the above
1.14 Which of the following permutations can be obtained in the output (in the same order) using a stack assuming that the input is the sequence 1, 2, 3, 4, 5 in that order?
(a) 3,4,5,1,2 (b) 3,4,5,2,1 (c) 1,5,2,3,4 (d)5,4,3,1,2