CSIR Engineering Sciences Question Paper with Answers June And December 2012

CSIR Engineering Sciences Question Paper with Answers June And December 2012CSIR Engineering Sciences Question Paper with Answers June And December 2012.

Junior Research Fellowship & Lectureship: CSIR NET Engineering Sciences 2012 question paper with answers CSIR NET Engineering Sciences June 2012 Question with solution you can download it in FREE, if CSIR NET Engineering Sciences 2012 paper in text or pdf for CSIR NET Engineering Sciences 2012 Answer Keys you can download CSIR NET Engineering Sciences 2012 page also just Go to menu bar, Click on File->then Save.

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CSIR Engineering Sciences Question Paper with Answers June And December 2012

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 What is the number of distinct arrangements of the letters of the word UGCCSIR so that U and I cannot come together?
1. 2520 2. 720 3. 1520 4. 1800

Suppose the sum of the seven positive numbers is 21. What is the minimum possible value of the average of the sqaures of these numbers?
1. 63 2. 21 3. 9 4. 7

 What is the next number in the sequence 24, 30, 33, 39, 51,-
1. 57 2. 69 3. 54 4. 81

Four lines are drawn on a plane with no two parallel and no three concurrent. Lines are drawn joining the points of intersection of the previous four lines. The number of  new lines obtained this way is
1.3 2.5 3.12 4.2

 Amar, Akbar and Anthony are three friends, one of whom is a doctor, another is an engineer and the third is a professor. Amar is not an engineer. Akbar is the shortest. The tallest person is a doctor. The engineer’s height is the geometric mean of the heights of the other two. Then which of the following is true?
1. Amar is a doctor and he is the tallest
2. Akbar is a professor and he is the tallest
3. Anthony is an engineer and he s shortest
4. Anthony is a doctor and he is the tallest

 For a flow to be incompressible
(1) density must be constant.
(2) velocity field must be divergence free.
(3) vorticity vector must be a null vector.
(4) streamline, streakline and pathline are identical.

 The net change in entropy at the end of a process undergone by a closed system turns out to be zero. The above process
– (1) must be reversible
(2) must be reversible and adiabatic
(3) must be irreversible and adiabatic
(4) may be irreversible, involving a net
heat transfer

CSIR Engineering Sciences Question Paper  December 2012

 

CSIR Engineering Sciences Answer keys December 2012

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